Monday, September 12, 2005

Roethlisberger perfect in 34-7 win over Titans

I won't pretend to understand the formula for passer rating in the NFL, both in its components and why the perfect rating is 158.3... but Ben Roethlisberger, in going 9 for 11 for 218 yards with 2 TDs and no INTs, garnered such a rating.

QUOTE(ESPN.com glossary)
Passer (QB) Rating

Rating Formula:
Step 1: Complete passes divided by pass attempts. Subtract 0.3, then divide by 0.2
Step 2: Passing yards divided by pass attempts. Subtract 3, then divide by 4.
Step 3: Touchdown passes divided by pass attempts, then divide by .05.
Step 4: Start with .095, and subtract interceptions divided by attempts. Divide the difference by.04.

The sum of each step cannot be greater than 2.375 or less than zero. Add the sum of the Steps 1 through 4, multiply by 100 and divide by 6.
http://sports.espn.go.com/nfl/news/story?id=2128923

Or, step by step:
9/11 = .8181 -.3 = .5181 / 0.2 = 2.59 for first step
218/11 = 19.81 - 3 = 16.81 / 4.20 for 2nd step
2/11 = .1818 / .05 = 3.6363 for 3rd step
0.95 - 0/11 = 0.95. Difference is 0

By the caveat, each of the first three steps yields a value greater than the max of 2.375, and step four has no subtractions from 2.375. So 2.375 x 4 = 9.5 * 100 = 950.0 / 6 = 158.3333

And that's enough to make your head spin. Good thing they have 'puters that are set to calc that automatically. It's a lot of gobbledegook. If there was no max, it would have been 2.59 + 4.20 + 3.63 + 2.375 = 12.795 * 100 = 1279.5 / 6 = 213.25 but that's meaningless since the step #4 INT calc has to have a max for it to work.

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